Day 22
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2024/day22/Cargo.lock
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2024/day22/Cargo.lock
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# This file is automatically @generated by Cargo.
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# It is not intended for manual editing.
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version = 3
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[[package]]
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name = "day22"
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version = "0.1.0"
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2024/day22/Cargo.toml
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2024/day22/Cargo.toml
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[package]
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name = "day22"
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version = "0.1.0"
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edition = "2021"
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[dependencies]
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2024/day22/README.md
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2024/day22/README.md
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# Solution Day 22
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One of the few later ones I actually did on the day. The pseudo-random number generator is easy enough to
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implement. If you read correctly, that is… I read "round to the nearest integer" first and was slightly off
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with my numbers, until I saw that little "down" in there, which makes the whole thing _much_ easier. You don't
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actually need to round, you can just do integer division, which will cut off the fractional part, leaving you
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with the already rounded-down number.
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## Task 1
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After implementing the pseudo-random generator, it's easy enough to run it 2000x for each start number and
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sum up the resulting numbers. Nothing special to see here.
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## Task 2
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This one was more complex. My initial naïve approach was to calculate all 4-digit sub-sequences, search for them
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in all sequences and sum up the assiciated price. While this would probably yield the result _at some point_, the
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complexity is _O(n² * m²)_ (with _n_ being the number of starting numbers and _m_ being the sequence length for each
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starting number, assuming I got my maths right). Let's just say: not fun, definitely too slow.
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My less naïve approach involves pre-calculating the first price of each sub-sequence for each starting number and
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then afterwards going through them, summing them up grouped by sub-sequence and finding the maximum number of those
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sums. This involves the heavy use of `HashMap`s (to keep track of the found sub-sequences and their associated number),
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but brings complexity down to _ O(n * m)_ (for all three steps, actually. Pre-calculating the sequences and prices is _O(n * m)_,
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calculating the sums and then finding the maximum is as well). This is then actually fast enough to finish before I
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get bored.
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2024/day22/src/main.rs
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2024/day22/src/main.rs
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#![feature(map_try_insert)]
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use std::collections::{HashMap, VecDeque};
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fn mix_and_prune(intermediate: i64, number: i64) -> i64 {
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(intermediate ^ number) % 16777216
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}
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fn next_secret_number(number: i64) -> i64 {
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let mut result = mix_and_prune(number * 64, number);
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result = mix_and_prune(result / 32, result);
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result = mix_and_prune(result * 2048, result);
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result
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}
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fn nth_secret_number(start: i64, n: u32) -> i64 {
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let mut result = start;
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for _ in 0..n {
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result = next_secret_number(result);
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}
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result
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}
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fn task1() {
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let numbers = include_str!("../input.txt")
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.lines()
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.map(|line| line.parse::<i64>().unwrap());
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let sum: i64 = numbers.map(|number| nth_secret_number(number, 2000)).sum();
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println!("Task 1: sum {sum}");
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}
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fn calculate_sequence(number: i64) -> HashMap<Vec<i64>, i64> {
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let mut current_number = number;
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let mut result = HashMap::new();
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let mut current_pattern = VecDeque::new();
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for _ in 0..2000 {
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let next_number = next_secret_number(current_number);
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let next_last_digit = next_number % 10;
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let current_last_digit = current_number % 10;
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current_pattern.push_back(next_last_digit - current_last_digit);
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if current_pattern.len() == 4 {
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// we're only ever interested in the first occurence of a pattern in the sequence, because that's what counts
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let _ = result.try_insert(
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Vec::from_iter(current_pattern.iter().cloned()),
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next_last_digit,
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);
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current_pattern.pop_front(); // throw away the first digit. The pattern is a sliding window over the sequence
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}
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current_number = next_number;
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}
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result
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}
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fn task2() {
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let numbers = include_str!("../input.txt")
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.lines()
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.map(|line| line.parse::<i64>().unwrap());
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let sequences: Vec<_> = numbers.map(calculate_sequence).collect();
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let mut banana_counters = HashMap::new();
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for sequence in sequences.iter() {
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for (pattern, price) in sequence.iter() {
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banana_counters.insert(
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pattern,
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banana_counters.get(pattern).unwrap_or(&0_i64) + price,
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);
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}
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}
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let sum = banana_counters.values().max();
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println!("Task 2: sum: {sum:?}");
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}
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fn main() {
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task1();
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task2();
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}
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